12.5-8.33x+x^2=0

Solution for 12.5-8.33x+x^2=0 equation:

12.5-8.33x+x^2=0

a = 1; b = -8.33; c = +12.5;
Δ = b2-4ac
Δ = -8.332-4·1·12.5
Δ = 19.3889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8.33)-\sqrt{19.3889}}{2*1}=\frac{8.33-\sqrt{19.3889}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8.33)+\sqrt{19.3889}}{2*1}=\frac{8.33+\sqrt{19.3889}}{2}
$